30x^2+41x-6=0

Solution for 30x^2+41x-6=0 equation:

30x^2+41x-6=0

a = 30; b = 41; c = -6;
Δ = b2-4ac
Δ = 412-4·30·(-6)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-49}{2*30}=\frac{-90}{60}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+49}{2*30}=\frac{8}{60}
=2/15
$